120=12t^2+2t

Solution for 120=12t^2+2t equation:

120=12t^2+2t

We move all terms to the left:

120-(12t^2+2t)=0

We get rid of parentheses

-12t^2-2t+120=0

a = -12; b = -2; c = +120;
Δ = b2-4ac
Δ = -22-4·(-12)·120
Δ = 5764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5764}=\sqrt{4*1441}=\sqrt{4}*\sqrt{1441}=2\sqrt{1441}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{1441}}{2*-12}=\frac{2-2\sqrt{1441}}{-24}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{1441}}{2*-12}=\frac{2+2\sqrt{1441}}{-24}
$